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Given the following half reactions:

MnO4- + 8H+ + 5e- –>Mn2+ + 4H2O    Eº = 1.51 V

Zn2+ + 2e- –> Zn                  Eº = -0.76 V

And information:

T = 25º C

[MnO4-] = 2.5 M

[H+] = 0.75 M

[Mn2+] = 1.0 x 10-3 M

[Zn2+] = 1.0 x 10-2 M

Calculate the cell potential with the Nernst equation.

ANSWERS HERE

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